Correct answer: Nc81...Bb5[a] 2.Q:b5#[A] 1...c:b6/[б]/ 2.Q:a3#[Б] 1...b:c6[c] 2.R:c6#[C] 1...d:c3 2.d4# 1...Bb2/Bc1/Bb4 2.Qb4# 1.Qb2[D]? zz 1...Bb5[a] 2.Q:
