Correct answer: Qh41...c:d1Q[a]/c:d1R[a] 2.Qf2#[A] 1...c:d1N/[б]/ 2.d4#[Б] 1...c:d1B 2.d4#[Б]/Qf2#[A] 1...Rb1/Ra2 2.Qd4# 1.R:c2? (2.d4#[Б]/Qf2#[A]) 1...R<