Correct answer: Qg21...Ng6[a]/Nf7/[б]/ 2.Nf7#[A] 1...N:d3[c]/Nd7[d]/Ne4[d]/Nb3[d]/Nb7[d]/Na4[d]/Na6[d] 2.Q:e6#[Б] 1...e:d5[e] 2.Qf5#[C] 1...f5 2.Qg7#