Correct answer: Nd21...Ke5/e:d5[a] 2.Bg7#[A] 1...e5/[б]/ 2.Be3#[Б] 1.Ng3? zz 1...e:d5[a] 2.Qb2#[C] 1...e5/[б]/ 2.N:f5#[D] 1...Ke5 2.Bg7#[A] 1...f4 2.Qe4# but
