Correct answer: Qh51...N:d2[a]/Nd6/Ne3/Nb2/Nb6/Na3/Na5 2.Nb6#[A] 1...Re3/[б]//Re2/[б]//Re1/[б]/ 2.R:d4#[Б] 1...Bh7/Be6[c] 2.Qe6#[C] 1.
