Correct answer: Bg51...d3[a] 2.R:e4#[A] 1...Ng5/[б]/ 2.Rf5#[Б] 1...Nd6[c]/Re6+[c] 2.Re6#[C] 1...Bd3 2.N:d3# 1...Ba2 2.R:e4#[A]/Nd3# 1...R:f4 2.g:f4# 1...<
