Correct answer: Qf21...Nf4[a] 2.Q:g7#[A] 1...Nf6/[б]/ 2.Qb8#[Б] 1...e6[c] 2.Nf3#[C] 1.Qf3? zz 1...Nf6/[б]/ 2.Q:g3#[D] 1...e6[c] 2.Nf7#[E] but 1...Nf4[a]!
