Correct answer: Qe61...Bb5/Re2[a] 2.N:b5#[A] 1...Bd4/[б]/ 2.Nd5#[Б] 1...B:g7 2.B:g7# 1.Qf5? (2.Q:f6#) 1...Re2[a] 2.Qd3#[C] 1...Bd4/[б]/ 2.Qc