Correct answer: Nd61...Nf6[a]/Nf8/[б]//Nb8/[б]/ 2.B:d4#[A] 1...Nc5[c] 2.Rd5#[Б] 1...Nb6[d] 2.Bb8#[C] 1...R:a7 2.R:e6# 1.Q:f1?? (2.Qf4#) but 1...d:c3!