Correct answer: Nd41...Nd2[a] 2.Ne3#[A] 1...Nd6/[б]/ 2.Ne7#[Б] 1...Ne3[c]/Nb2[d]/Nb6[d]/Na3[d] 2.Qe4#[C] 1...Qc6 2.Q:c4# 1...e4 2.f:e4# 1.Rd2?? (2.N