Correct answer: Kc31...Ng3[a]/Nh2/[б]//Ne3/[б]//Nd2[a] 2.Ke3#[A] 1...N:c5[c] 2.K:c5#[Б] 1...Bc2/Bd1/Bc4 2.Kc4# 1.Bf5? (2.Ke4#) 1...Ng3[a]/
