Correct answer: Qh41...Rc4[a] 2.Nd3#[A] 1...Nd4/[б]/ 2.Nd7#[Б] 1...N:c6 2.R:c6# 1.Qg4? (2.Qb4#) 1...Rc4[a] 2.Q:c4#[D] 1...Nd4/[б]/ 2.Q:d4#[C]
