Correct answer: Nd51...R:c5+ 2.N:c5# 1.Nc2? (2.Qb4#[A]/Qa3#[Б]) 1...Nc4[a] 2.Qb4#[A] 1...Nc6/[б]/ 2.Qa3#[Б] 1...R:c5 2.N:c5# 1...Bc4/B
