Correct answer: Kc41...Nf3/Ng2 2.N:f3#[A] 1...Nd3/Nc2 2.N:d3#[Б] 1...f3 2.Q:h2# 1...B:g1/Bg3 2.Qh5# 1.Qg2? (2.Qg5#/Qg7#) 1...c5 2.Qg7#