Correct answer: Na31...f3[a] 2.R2h4#[Б] 1...f5/[б]/ 2.Q:g7#[C] 1...d:c2[c]/d2 2.Rd2#[D] 1...c:b4[d]/c4 2.Q:b6#[E] 1...Bc1/Ba3 2.c3#[A] 1...Ba1 2.Q:a1# 1...b5 2.Q:c5# 1.