Correct answer: Qf31...Be4[a] 2.Qa1#[A] 1...Re4/[б]/ 2.Qa5#[Б] 1.Qg2? (2.Nc6#) 1...Be4[a] 2.Q:h2#[C] 1...Re4/[б]/ 2.Qg5#[D] but 1...Bf5! 1.Q