Correct answer: Qc21...Rc4[a] 2.Q:d7#[A] 1...Nc4/[б]/ 2.Q:a8#[Б] 1...Nc1/Nc5/Nd2/Nd4/Na1 2.Qc5# 1.Qc3? (2.Nc7#) 1...Rc4[a] 2.Qe5#[C]