Correct answer: a41...Qe1[a]/Qg1/Qh1/Qe2[a] 2.Qb3#[A] 1...Rd5/[б]/ 2.Qb4#[Б]/Qa6# 1...Qc1/Qb1/Qa1/Qf1/Qb3 2.K:f3#/Qb3#[A] 1...Qc2/