Correct answer: a71...Nd7[a] 2.Bd5#[A]/B:d7#[Б] 1...N:a6/[б]/ 2.Q:a6#[C] 1...Bb3/Bc2/B:d1/Bb5 2.Qb5# 1.Qb4? zz 1...Nd7[a] 2.Bd5#[A]/B:d7#[
