Correct answer: Bb71...Nc5[a] 2.Nd6#[Б]/Nb6#[A] 1...Ne1/N:e5/Nf4/Nb2/Nb4/[б]/ 2.Qb3#/Nb6#[A] 1...Nc1 2.Nb6#[A] 1.Bb4? (2.Nd6#[Б]/Nb6#[A]
