Correct answer: Qg51...Nf4[a] 2.Qb2#[A] 1...Nd4/[б]/ 2.Qh2#[Б] 1...d6 2.Bg5#/Bh4# 1.Q:b4? (2.Bg5#) 1...Nf4[a] 2.Qc3#[D] 1...Kf4/Nd4/[б]/ 2.Q