Correct answer: Nd71...Ng3[a]/Ng7[a]/Nf4[a]/Nf6/[б]/ 2.N:g3#[A] 1...Nc5[c]/Nd6[c]/Nd8[c]/Na5[c] 2.Nd6#[Б] 1.Kg4? zz 1...Ng3[a]/Ng7[a]/Nf4[a]
