Correct answer: Bd21...Ra1/Rd2+[a]/Bb2 2.Qd2#[A] 1.Bb2? (2.Qc1#[Б]/Qd2#[A]) 1...Bb4[c] 2.Qc1#[Б] 1...Ra1/B:b2 2.Qd2#[A] but 1...R:b2/[б]/!