Correct answer: Qb71...Kd1[a]/Nf1[c]/Ng2[d]/Ng4 2.Qa1#[A] 1...Kf1/[б]//Nd1[e]/Nc2[f] 2.Qg1#[Б] 1...Nf5/Nd5/Nc4 2.Qg1#[Б]/Qa1#[A] 1.Qg5?