Correct answer: Qc81...Bh3[a]/Bf3[a] 2.Qf3#[A] 1...Bh5/[б]//Be2/[б]//Bd1/[б]//Bf5+/[б]/ 2.Qf5#[Б] 1...Rb6/Rb7/Rb8/Rc5 2.Nc5# 1...Nc3/Nd2/
