Correct answer: d41...B:c5[a]/d:c5[d] 2.Nc3#[A] 1...Be4/[б]/ 2.d:e4#[Б] 1...Nc4[c] 2.d:c4#[C] 1...Bb6/Bb8 2.N:b6# 1...f4 2.Qh5# 1...Bh1 2.Q:h1# 1...Bf1/Bf