Correct answer: Be21...Ke4[a] 2.Qe5#[A] 1...Nf3/[б]//Ng2[c]/Nc2/[б]/ 2.Q:d3#[Б] 1.B:e1? (2.Q:d3#[Б]/Qe5#[A]) but 1...Ke4[a]! 1.Kf5?? zz 1...Nf3/[б]