Correct answer: Nc51...Nd3[a]/Ne2[a]/Nb3[a]/Na2[a] 2.Ne2#[A] 1...Ne8/[б]//Nb5/[б]//Na8/[б]/ 2.Nb5#[Б] 1...Bc5[c] 2.Q:c5#[C] 1.Kf3? zz 1...Nd3[a]/
