Correct answer: e41...f3[a] 2.Qd3#[A] 1...Nc7 2.R:c7# 1...Qb3 2.Bd3# 1...b3 2.Bd3#/B:b3# 1.Nb5[Б]? (2.Nd6#) 1...f3[a] 2.Qd3#[A] 1...d3/[б]/ 2.Bd1#[C]