Correct answer: Rd51...Nc7[a] 2.Nd8#[A] 1...Bb3/Bc2/Bd1 2.b5# 1...Nb6 2.Na5# 1...d:e6 2.Bb7# 1.R:d7? (2.R:d6#[Б]/Nd8#[A]) but 1...d5! 1.Ba6?? zz
