Correct answer: Nd41...Qb5[a]/b5 2.Qf8#[Б] 1...Qb2/Qb1/Qc2/Qd1/Qc4/[б]/ 2.Qc4#[A] 1.Rb4? (2.Qf8#[Б]/Qb5#[C]) 1...Qc4/[б]/ 2.Qf8#[Б]/Q:c4#[A]
