Correct answer: Ba71...Qe4+[a] 2.B:e4#[A] 1...Qb7+/[б]/ 2.B:b7#[Б] 1...Qd5 2.B:d5#/Qf1# 1...Qc6 2.B:c6#/Qf1# 1...Q:a8 2.Qf1# 1.Bg3? zz 1...
