Correct answer: Nd51...c:b4 2.Rd4# 1...B:g4/Bd1 2.Bd3# 1...Bd3 2.Bg2#/B:d3# 1.Bh6? (2.Rf4#[A]) 1...Bf3/[б]/ 2.Bd3# 1...e5 2.Nd2#[Б] but 1...B<