Correct answer: Na51...b:a4[a] 2.Na6#[A] 1...b:c4/[б]/ 2.Nc6#[Б] 1.Nc1?? (2.Qb3#/Nd3#/Na2#) 1...b:a4[a] 2.R:a4#/Nd3#/Na2#/Q:a4# 1...b:c4/[б]/ 2.Na2# 1.
