Correct answer: Qd41...Nd2[a]/Ne3[a]/Nb2[a]/N:b6[c]/Na3[a]/Na5[a] 2.Qg3#[A] 1...Ne5/[б]/ 2.Qe7#[Б] 1...B:e6[d]/Be8[e]/Bc6[f]/B:b5[g]/Bc8[e] 2.B