Correct answer: Qg51...Ke3[a] 2.Ng4#[A] 1...Kc5/[б]/ 2.Ned3#[Б] 1...Nd6 2.Bb6# 1...Ne7/Nb6/Na7 2.Bb6#/Qb6# 1.Qh4? (2.Qf2#) 1...Ke3[a] 2.