Correct answer: d8N1.d8R? (2.Be3#[A]) but 1...Kb6[a]! 1.d8B? (2.Rh5#[Б]) but 1...Kd5/[б]/! 1.d8N! zz 1...Kb6[a] 2.Be3#[A] 1...Kd5/[б]/ 2.Rh5#[Б