Correct answer: Qd21...f4[a] 2.Rc5#[A] 1...Nf4/[б]/ 2.Nf7#[Б] 1.Qe3?? (2.Nf7#[Б]/Rc5#[A]/Re6#) 1...f4[a] 2.Rc5#[A] 1...Nf4/[б]/ 2.Nf7#[Б]/Qd4#[C] 1...<
