Correct answer: Nf61.Qb6? (2.Qb1#[A]/Q:d4#[Б]) 1...d:c3[a] 2.Nb4#[C]/Qd4#[Б] 1...Bg7 2.Qb1#[A] 1...a2 2.Q:d4#[Б] but 1...a:b6! 1.Qe5? (2.Q:d4#[Б]) but 1...<
