Correct answer: Ne41...Nc3[a] 2.Bc2#[A] 1...Ne3/[б]/ 2.Be2#[Б] 1...Be4/Bf3/Bg2/Bh1 2.N:e4# 1...Bf7/Bg8 2.N:f7# 1...Bc4+/B:b3 2.N:c4# 1.
