Correct answer: Qd51.Qg7? zz 1...c:d6[a] 2.Qb7#[Б] 1...Ka7/[б]/ 2.Qa1#[A] but 1...Ba7! 1.Qe4?? zz 1...Ka7/[б]/ 2.Qa4# 1...Ba7 2.K:c7# but 1...c:d6[a]!
