Correct answer: Qf41...Ne4[a] 2.c4#[A] 1...Ne8/[б]//Nf5/[б]//Nf7/[б]//Nc8/[б]//Nb5/[б]/ 2.e4#[Б] 1...Nc4[c] 2.Qc6#[C] 1.e4+[Б]?? 1...N:e4[a] 2.c4#[A] but 1...Ke6!