Correct answer: Qc81...Nc4[a] 2.Qf3#[A] 1...Nc6/[б]/ 2.Q:b3#[Б] 1.Qc2?? (2.Qe4#) but 1...b:c2! 1.Qc1?? zz 1...Nc4[a] 2.Qh1# but 1...Nc6/[б]/! 1.Qc7
