Correct answer: Nd71.Bc7? (2.Qb8#) 1...Rg1[a] 2.Ng6#[A] 1...Re1/[б]/ 2.Ne6#[Б] but 1...Re8! 1.Nd7! (2.Qb8#) 1...Rg1[a] 2.Bg5#[C] 1...R