Correct answer: Qd61...Kf3[a] 2.Qa8#[A] 1.Qa1? zz 1...Kf3[a] 2.Qa8#[A] 1...Kf5/[б]/ 2.Bd3#[Б] but 1...e5! 1.Qb2? zz 1...Kf3[a] 2.Bc6#[C] 1...K