Correct answer: B:c41...B:c5[a]/d:c5 2.Qe4#[A] 1.R:d6[Б]? (2.Ne6#) 1...B:c5[a] 2.Qe4#[A] 1...K:c5/[б]/ 2.Qb6#[C] 1...N:c5[c] 2.B:c4#[D] but 1...Nc7!