Correct answer: Bd71...Ke4[a] 2.N:f6#[A] 1.Be2? (2.Qc4#[C]) 1...Ke4[a] 2.Qd3#[Б] but 1...Ke6! 1.Bf4? (2.N:f6#[A]) 1...Ke4[a] 2.Qc4#[C] but 1...f5!
