Correct answer: Bd11...Nd6[a]/Bd6[c] 2.Nf6#[Б] 1...Ne5/Be5/[б]/ 2.Ne7#[A] 1...Rc5/Nc5[d] 2.Nb6#[C] 1.Re4? (2.Ne7#[A]) 1...Bd6[c] 2.Nf6#[Б] but
