Correct answer: Qa51...Bg2/Bh3[a] 2.Qb3#[A] 1...B:c5/[б]/ 2.Q:c5#[C] 1...B:e3 2.N:e3# 1...B:c3 2.N:c3#[Б] 1.N:f1?? (2.Qb3#[A]) 1...B:e3 2.Nd:e3
