Correct answer: Bg51...Qd6/Q:f7[a]/Qd7 2.f:e4#[A] 1...Qc8 2.f:e4#[A]/Qc5#[Б] 1.Ng5? (2.Ng7#/B:e6#) 1...Qf7[a]/Qg8/Qd7 2.f:e4#[A] 1...Rb3/Qe5/[
